The emitter voltage Ve,  is Vb - 0.6 = 0.4 volts.

The emitter current is Ve / Re = 0.0008A

The voltage across the 5K load resistor is 5000 x .0008 = 4 volts

Therefore the collector voltage is 10 volts - 4 volts = 6 volts

The power dissipated by the transistor is the voltage acrooss the transistor mutiplied by the current through it. = 5.6 volts x 0.0008A = 0.00448 watts